std::chrono::year_month::operator+=, std::chrono::year_month::operator-=

来自cppreference.com
< cpp‎ | chrono‎ | year month

 
 
 
 
constexpr std::chrono::year_month&
    operator+=( const std::chrono::years& dy ) const noexcept;
(1)(C++20 起)
constexpr std::chrono::year_month&
    operator+=( const std::chrono::months& dm ) const noexcept;
(2)(C++20 起)
constexpr std::chrono::year_month&
    operator-=( const std::chrono::years& dy ) const noexcept;
(3)(C++20 起)
constexpr std::chrono::year_month&
    operator-=( const std::chrono::months& dm ) const noexcept;
(4)(C++20 起)

以时长 dydm 为程度修改 *this 表示的时间点。

1) 等价于 *this = *this + dy;
2) 等价于 *this = *this + dm;
3) 等价于 *this = *this - dy;
4) 等价于 *this = *this - dm;

对于能转换到 std::chrono::yearsstd::chrono::months 两者的时长,若调用有歧义,则偏好 years 的重载 (1,3)

示例

#include <cassert>
#include <chrono>
 
int main()
{
    auto ym{std::chrono::day(1)/7/2023};
 
    ym -= std::chrono::years{2};
    assert(ym.month() == std::chrono::July);
    assert(ym.year() == std::chrono::year(2021));
 
    ym += std::chrono::months{7};
    assert(ym.month() == std::chrono::month(2));
    assert(ym.year() == std::chrono::year(2022));
}

参阅

进行 year_month 上的算术
(函数)